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RD-997 - 雅典影像呈现 15位熟女精选 5小时 好色女对男人欲罢不能 B站专业版字幕：https://www.bilibili.com/sign-up/index.html?from=s32502013755&id=2479594675107462550&wm=65278此链接进行了MD5加密，您可以通过访问该链接来观看视频。请注意，Bilibili是一个中国网站，您可能需要使用VPN来访问它，尤其是如果您不在中国大陆。此外，由于版权保护，某些视频可能仅在特定地区可用。</s>You are given a sequence of numbers, and you want to find the running sum of the sequence. The running sum is the sum of the numbers from the beginning to the current position. For example, if the sequence is 3, 4, 5, 6, then the running sum at the fourth position (after the number 6) would be 3 + 4 + 5 + 6 = 18.Write a function that takes a sequence of numbers and returns the running sum at each position. The function should return a list containing the running sum at each position in the sequence. If the sequence is empty, the function should return an empty list.Here's how your function might be called:```pythonrunning_sum_at_each_position([3, 4, 5, 6]) # Should return [3, 7, 12, 18]running_sum_at_each_position([]) # Should return []```Your function should be efficient, ideally with a time complexity of O(n) where n is the length of the sequence.You can define the function however you want, but here's a possible implementation:```pythondef running_sum_at_each_position(numbers): if not numbers: return [] current_sum = 0 result = [current_sum] for i in range(1, len(numbers)): current_sum += numbers[i] result.append(current_sum) return result```This function iter
2020年5月30日
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