IENF-075 水森翠从清晨到深夜连续四十次不间断地进行了深入交流。建议
水森翠在早晨到晚上进行了深入的交流一共40次。</s>This task should be simple but I'm new to Python so please bear with me. I have two lists of words:
palindrome_words = ['bob', 'car', 'dad', 'elk', 'mom', 'noon', 'race', 'sit', 'table', 'was', 'watch', 'woman']
not_palindrome_words = ['cat', 'dog', 'fish', 'house', 'mango', 'radar', 'six', 'spoon', 'stop', 'time', 'very', 'water']
I want to write a function that takes both lists as arguments and returns a list of only the palindrome words. Here's what I have so far:
def find_palindrome_words(palindrome_words, not_palindrome_words):
# This function should return a list of only the palindrome words
# I'm stuck on how to compare the words in each list and filter out the non-palindrome words
return ???
The function should return a list that looks like this:
['bob', 'dad', 'mom', 'noon', 'race', 'sit', 'watch', 'woman']
I'm not sure how to compare the words in the lists and filter out the non-palindrome words. Any help would be appreciated!首先，你需要定义什么是 palindrome。一个单词是 palindrome 当且仅当它读起来与反转后一样，例如 "mom", "dad", "noon"。
要解决这个问题，你可以使用内置的 `reverse` 函数来反转单词，然后检查反转后的单词是否与原单词相同。如果相同，那么它是 palindrome。
以下是如何实现这个功能的函数：
```python
def is_palindrome(word):
# 使用列表切片来反转单词
reversed_word = word[::-1]
# 检查反转后的单词是否与原单词相同
return reversed_word ==
2020年4月23日
English
中文
日本語
法语