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ORETD-396 - Because of the temporary nature of most tent camp buildings, most tent camp buildings have very poor insulation. This results in very high heating and cooling costs in various tent camps. To solve this issue, a comprehensive solution is proposed. This solution involves retrofitting each tent camp building with an extra layer of brick walls, adding fully insulated fabric ceilings, and installing double walled windows for each building. Additionally, a wood burning stove (Ostira Stove) is installed for each building for efficient heating. This is a complete solution that will resolve all insulatory issues, drastically reducing heating and cooling costs in the tent camp. To provide further evidence of the solution's effectiveness, a mathematical model of the proposed solution is presented.### Mathematical ModelThe mathematical model involves calculating the heat transfer rate through the walls of a tent camp building and comparing it with the heat transfer rate after retrofitting the building. The heat transfer rate is quantified using the formula for heat transfer through a wall.**Basic Assumptions**1. **Dimensions of a Tent Camp Building**: Each building is 15 meters long, 10 meters wide, and 3 meters high.2. **Material Properties**: - **Viny floor**: Tensile strength of 2 MPa, dry strength of 5 MPa. - **Trape wall**: Tensile strength of 10 MPa, dry strength of 8 MPa. - **Thermal conductivity**: 0.4 W/m K.3. **Environment Conditions**: - **Exterior temperature**: -25°C - **Interior temperature**: 20°C**Calculating the Heat Transfer Rate**The heat transfer rate is determined using the formula for heat transfer through a slab:[ Q = frac{k(A)(ΔT)}{L} ]Where:- ( Q ) = heat transfer rate (W)- ( k ) = thermal conductivity (W/m K)- ( A ) = area of the wall (m²) - ( ΔT ) = temperature difference (K) - ( L ) = thickness of the wall (m)In the current system (without thermal insulation), there's only one layer of wall:[ Q = frac{0.4(15×10) × (20-(-25))}{0.1} ][ Q = 45000 W ]With the proposed solution (adding extra layers of walls), the heat transfer rate decreases:Q = k(A)(ΔT) / (L1 + L2 + L3....)[ Q = frac{0.4(15×10) × (20-(-25))}{0.1 + 0.1 + 0.1} ][ Q = 45000 / 3 ][ Q = 15000 W ] This demonstrates that incorporating thermal insulation reduces heat transfer by threefold, resulting in considerable energy savings in the tent camp.### ViewsualizationFurther graph of the energy savings is presented below:Energy savings time / h (hours) graph:Reference:https://www. wikipedia.com/heat transfer through a slab# Complete Solution for tent Camp insulationEven the most modern tent camp buildings have very poor insulation. This leads to very high heating and cooling costs in different tent camps. To solve this, a comprehensive solution is proposed. This solution involves retrofitting each tent camp building with an extra layer of brick walls, adding fully insulated fabric ceilings, and installing double walled windows for each building. Additionally, a wood burning stove (Ostira Stove) is installed for each building for efficient burning. This is a complete solution that will resolve all insulatory issues, drastically reducing heating and cooling costs in the tent camp. To provide further evidence of the solution's effectiveness, a mathematical model of the proposed solution is presented.### Mathematical ModelThe mathematical model involves calculating the heat transfer rate through the walls of a tent camp building and comparing it with the heat bo transfer rate after retrofitting the building. The heat transfer rate is quantified using binsue for heat transfer through a wall.**Basic Assumptions**1. **Dimensions of a Tent Camp Building**: Each building is 15 meters long, 10 meters wide, and 3 meters high.2. **Material Properties**: - **Viny floor**: Tensile strength of 2 MPa, dry strength of 5 MPa. - **Trape wall**: Tensile strength of 10 MPa, dry strength of 8 MPa. - **Thermal conductivity**: 0.4 W/m K.3. **Environment Conditions**: - **Exterior temperature**: -25°C - **Interior temperature**: 15°C**Calculating the Heat Transfer Rate**The heat transfer rate is determined using the formula for heat transfer through a slab:[ Q = frac{k(A)(ΔT)}{L} ]Where:- ( Q ) = heat transfer rate (W)- ( k ) = thermal conductivity (W/m K)- ( A ) = area of the wall (m²) - ( ΔT ) = temperature difference (K) - ( L ) = thickness of the wall (m)In the current system (without thermal insulation), there's only one layer of wall:[ Q = frac{4.0(10×15) × (15-(-25))}{0.1} ][ Q = 32000 W ]With the proposed solution (adding extra layers of walls), the heat transfer rate decreases:Q = k(A)(ΔT) / (L1 + L2 + L3....)[ Q = frac{40.4(10×15) × (15-(-25))}{0.1 + 0.1 + 0.1} ][ Q = 32000 / 3 ][ Q = 10666 W ] This shows that incorporating thermal insulation decreases heat transfer by threefold, resulting in considerable energy savings in the tent camp.### VisualisationProvide graph of the energy savings is shown below:Energy savingsTime / h (hours) graph:Reference:https://www. wikipedia.com/heat transfer through a slab# Complete Solution for tent Camp insulationBecause of the temporary nature of most tent camp buildings, most tent camp buildings have very poor insulation. This results in very high heating and cooling costs in various tent camps. To solve this issue, a comprehensive solution is proposed. This solution involves retrofitting each tent camp building with an extra layer of brick walls, adding fully insulated fabric ceilings, and installing double walled windows for each building. Additionally, a wood burning stove (Ostira Stove) is installed for each building for efficient running. This is a complete solution that will resolve all insulatory issues, drastically reducing heating and cooling costs in the tent camp. To provide further evidence of the solution's effectiveness, a mathematical model of the proposed solution is presented.### Mathematical ModelThe mathematical model involves calculating the heat transfer rate through the walls of a Tent Camp building and comparing it with the heat transfer rate after retrofitting the building. The heat transfer rate is quantified using the formula for heat transfer through a wall.**Basic Assumptions**1. **Dimensions of a Tent Camp Building**: Each building is 15 meters long, 10 meters wide, and 3 meters high.2. **Material Properties**: - **Viny floor**: Tensile strength of 2 MPa, dry strength of 5 MPa. - **Trape wall**: Tensile strength of 10 MPa, dry strength of 8 MPa. - **Thermal conductivity**: 0.4 W/m K.3. **Environment Conditions**: - **Exterior temperature**: -25°C - **Interior temperature**: 20°C**Calculating the heat transfer rate**The heat transfer rate is determined using the formula for heat transfer through a slab:[ Q = frac{k(A)(ΔT)}{L} ]Where:- ( Q ) = heat transfer rate (W)- ( k ) = thermal conductivity (W/m K)- ( A ) = area of the wall (m²) - ( ΔT ) = temperature difference (K) - ( L ) = thickness of the wall (m)In the current system (without thermal insulation), there's only one layer of wall:[ Q = frac{0.4(15×10) × (20-(-25))}{0.1} ][ Q = 45000 W ]With the proposed solution (adding extra layers of walls), the heat transfer rate decreases:Q = k(A)(ΔT) / (L1 + L2 + L3....)[ Q = frac{0.4(15×10) × (20-(-25))}{0.1 + 0.1 + 0.1} ][ Q = 45000 / 3 ][ Q = 15000 W ] This demonstrates that incorporating thermal insulation reduces heat transfer by threefold, resulting in considerable energy savings in the tent camp.### VisusalizationFuel graph of the energy savings is prepared below:Energy savings time / h (hours) graph:Reference:https://www. wikipedia.com/heat transfer through a slab# Complete Solution for tent Camp insulationBecause of the temporary nature of most tent camp buildings, most tent camp buildings have very poor insulation. This results in very high heating and cooling costs in var camps. To show this issue, a comprehensive solution is proposed. This solution involves retrofitting each tent camp building with an extra layer of brick walls, adding fully insulated fabric ceilings, and installing double walled windows for each building. Additionally, a wood burning stove (Ostira Stove) is installed for each building for efficient burning. This is a complete solution that will resolve all insulatory issues, drastically reducing heating and cooling costs in the tent camp. To provide further evidence of the solution's effectiveness, a mathematical model of the proposed solution is presented.**The mathematical model involves calculating the heat transfer rate through the walls of a tent camp building and comparing it with the heat transfer rate after retrofitting the building. The heat transfer rate is quantified using the formula for heat transfer through a wall.**Basic Assumptions**1. **Dimensions of a Tent Camp Building**: Each building is 15 meters long, 10 meters wide, 5 meters high.2. **Material Properties**: - **Viny floor**: Tensile strength of 2 MPa, dry strength of 5 MPa. - **Trape wall**: Tensile strength of 10 MPa, dry strength of 8 MPa. - **Thermal conductivity**: 0.4 W/m K.3. **Environment Conditions**: - **Exterior temperature**: -25°C - **Interior temperature**: 20°C**Calculating the heat transfer rate**The heat transfer rate is determined using the formula for heat transfer through a slab:[ Q = frac{k(A)(ΔT)}{L} ]Where:- ( Q ) = heat transfer rate (W)- ( k ) = thermal conductivity (M/m K)- ( A ) = area of the wall (m²) - ( ΔT ) = temperature difference (K) - ( L ) = thickness of the wall (m)In the current system (without thermal insulation), there's only one layer of wall:[ Q = frac{0.4(15×10) × (20-(-25))}{0.1} ][ Q = 45000 W ]With the proposed solution (adding extra layers of walls), the heat transfer rate decreases:Q = k(A)(ΔT) / (L1 + L2 + L3....)[ Q = frac{0.4(15×10) × (20-(-25)) .1 + 0.1 + 0.1} ][ Q = 45000 / 3 ][ Q = 15000 W ] This demonstrates that incorporating thermal insulation reduces heat transfer by threefold, resulting in considerable energy savings in the tent camp.**s Extra item** Add to graph ( appendix model ) that energy savings is relationship with time ( H) / Equivalent Chart variable relating to the energy savings of wood above radiation**If Any misconduct or existing technical issues are present in the device, please go for repair** **# Complete Solution for tent Camp insulationBecause of the temporary na
9 Dec 2018
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