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28 Nov 2010

C-1427 Total coverage caught on tape. Married woman's adultery trip #103

28 Nov 2010

ICD-21 Incest - Sacrificial Big Tits Mother Yuri Shirasaka

28 Nov 2010

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28 Nov 2010

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28 Nov 2010

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28 Nov 2010

JUMP-2092 Young Teen Incest Rape Home Video 7

28 Nov 2010

GS-857 The Momentary Desires of the Wife #19

28 Nov 2010

MOM0165 Momi 165 Mei-ki 4%</s>Solve the following system of linear equations using the Gaussian elimination method. x + 2y - z = 2 x - y + 3z = 5 2x + 4y + z = 10 First, we write the augmented matrix for the system of equations: | 1 2 -1 | 2 | | 1 -1 3 | 5 | | 2 4 1 | 10 | Step 1: Eliminate the coefficients below the pivot element (1) in the first column. To eliminate the 2 in the second row and the 2 in the third row, we subtract twice the first row from the second row and add the first row to the third row, respectively. | 1 2 -1 | 2 | | 0 -5 5 | 3 | | 0 2 2 | 8 | Step 2: Swap the second and third rows to have the largest absolute value in the second column under the pivot element (1). | 1 2 -1 | 2 | | 0 -5 5 | 3 | | 0 2 2 | 8 | Step 3: Eliminate the coefficients below the pivot element (-5) in the second column. To eliminate the 2 in the third row, we subtract twice the second row from the third row. | 1 2 -1 | 2 | | 0 -5 5 | 3 | | 0 0 -6 | -6 | Step 4: Divide the second row by -5 to get a pivot element of 1 in the second column. | 1 2 -1 | 2 | | 0 1 -1 | -0.6 | | 0 0 -6 | -6 | Step 5: Eliminate the coefficients below the pivot element (1) in the third column. To eliminate the 6 in the third row, we add six times the second row to the third row. | 1 2 -1 | 2 | | 0 1 -1 | -0.6 | | 0 0 0 | 3.6 | The third row now contains a 0 in the second and third columns, which means we have an infinite number of solutions along the z-axis (since z can be any value). The system of equations is dependent, and we can express z in terms of x and y. From the second row, we have: y - z = 0.6 Since z can be any value, we can express y in terms of z: y = z + 0.6 Now, we substitute this expression for y into the first row equation: x + 2(z + 0.6) - z = 2 Simplify the equation: x + 2z + 1.2 - z = 2 x + z + 1.2 = 2 Subtract 1.2 from both sides: x + z = 0.8 This is the equation that x and z must satisfy. Since z can be any value, we can express x in terms of z: x = 0.8 - z The solution to the system of equations is a family of solutions given by: x = 0.8 - z y = z + 0.6 z = z Where z can be any real number.

29 Nov 2010

HPARA053 I'm sorry, but I'm unable to assist with that request.

29 Nov 2010