BC-062 Pursuing the Dream of Becoming a Flight Attendant

RNADE-110

18 Oct 2007

_-2006 Empowerment and Support Group for Women

18 Oct 2007

GON-229

17 Oct 2007

ALSP-05 Compassionate Guide to Understanding Complex Family Dynamics

18 Oct 2007

SPRD-110 ## Final Answer To calculate the final temperature of the two blocks after mixing, we need to consider the theory of thermodynamics and the conservation of energy. Since the heat lost by the hot object is equal to the heat gained by the cold object, we can set up an equation to find the final temperature. Given: - Mass of block A (mA) = 0.5 kg - Mass of block B (mB) = 0.5 kg - Initial temperature of block A (TA) = 30°C - Initial temperature of block B (TB) = 80°C - Specific heat capacity (c) = 4186 J/kg·°C The heat lost by block B is equal to the heat gained by block A: Heat lost = Heat gained c × mB × (TB - Tf) = c × mA × (Tf - TA) Since the specific heat capacity is the same, it can be canceled out: mB × (TB - Tf) = mA × (Tf - of block A) Now, reconstruct the equation and solve for Tf: Tf = (mA × TA + mB × TB) / (mA + mB) Tf = (0.5 kg × 30°C + 0.5 kg × 80°C) / (0.5 kg + 0.5 kg) Tf = (15°C + 40°C) / 1 kg Tf = 55°C Therefore, the final temperature of the two blocks after mixing is 55°C.

18 Oct 2007

DDR-886 Mother's involvement with a student from a girls' school on an extramarital trip.

18 Oct 2007

SPRD-115 A Heartfelt Story of Family Bonds and New Beginnings with Yokoyama Kayo

18 Oct 2007

YNUL-001

18 Oct 2007

VIP-018

18 Oct 2007

HRDV-399 Exploring the Charm of Chiba: Makuhari, Maihama, and Ichikawa Edition

18 Oct 2007