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ANND-016 English DVD Cover 116 minutes

ANND-016 A visually appealing mature woman, Yuki Kurishima, devours the world with her blonde, large-breasted dynamite body.

19 Aug, 2008116 mins


Release Date

19 Aug, 2008

Movie Length

116 minutesNormal

Director

Masaru Onodera

Studio / Producer

Anna and Hanako

Popularity Ranking

122515 / 517207

Other Names

annd016, ANND016, ANND 016

Total Actresses

1 person

Actress Body Type

Voluptuous, Average Height

Uncensored

No

Language

Japanese

Subtitles

SubRip (SRT file)

Copyright Owner

DMM

Featured Actress: Kaoru Kisaragi

Cup Size: -
Height: -
Measurements: -
Blood Type: -

Pricing & Formats

Streaming (HD/4k) ¥300

Standard (480p) ¥480

Subtitles & Translations

English Subtitles

Chinese Subtitles

Japanese Subtitles

French Subtitles

Frequently Asked Questions

What does the code ANND-016 mean?

Every Japanese adult video has a 'JAV code' (identification number) that represents each unique video that's produced.

In this case, 'ANND' refers to the producer's video series (category), and '016' refers to the episode number.

Is there an uncensored version for this movie?

Unfortunately not. At this point in time, there isn't an uncensored version for ANND-016 JAV.

In fact, all movies produced and sold by Momotaro Eizo production studio are censored.

Where can I download the full verison of this movie?

Click the 'Download' button on the top of this page to purchase and instantly download ANND-016's complete movie from the official seller's website (DMM).

There are 2 pricing options to buy this movie from the official website. The first is a single-video purchase (depending on resolution), where you can download or stream the complete movie after making your payment. The second is a membership for a fixed monthly price, where you can download an unlimited number of videos after subscribing.

I want to download the free preview trailer for this video. Is this possible?

Unfortunately, it is not possible to download the free preview trailer for ANND-016.

You can however, watch the free preview trailer by scrolling to the top of the page and clicking the 'PLAY' button.

Where can I download ANND-016 English subtitles?

To download ANND-016 English subtitles, scroll to the top of the 'Subtitles' section above and click on 'Order' (next to 'English Subtitles').

Similar to ANND-016

DYM-009 2. A rocket’s motion is given by the equation: y(t) = a x + b and the rocket’t at a hot coin: he equation for calculating the rocket’s motion is: y(t) = a x + b and the rocket’s motion can be determined by its acceleration. Determine the acceleration from the equation of motion: a(t) = -0.65t + b. Find the acceleration for the rocket. The final state velocity is 15.3 m/s. calculate the time taken for the rocket to reach this final state velocity. Players are placed in a space. To solve this problem, we’ll need to make several assumptions, as the information provided is incomplete. For instance, we’ll assume that the acceleration is given by a(t) = -0.65t + b, and that the initial velocity of the rocket is 0 m/s. Here’s how we’ll approach the problem: 1. **Determine the initial velocity:** Let’s assume that the initial velocity of the rocket is 0 m/s. 2. **Use the equation of motion:** The equation of motion is given as y(t) = a x + b. Since a(t) = -0.65t + b, we can infer that the acceleration is given by -0.65t + b. Here, b is the initial acceleration, which we’ll assume is 0 m/s². This simplifies the acceleration to -0.65t. 3. **Calculate the final state velocity:** The final state velocity is given as 15.3 m/s. Let’s find the time taken for the rocket to reach this velocity. 4. **Use the velocity equation:** The rate of change of velocity is the acceleration. Therefore, the final velocity can be determined as the integral of the acceleration. That is: ``` v(t) = ∫ a(t) dt = ∫ -0.65t dt v(t) = -0.65t² / 2 + C ``` Here, C is the initial velocity, which is 0 m/s. Therefore, the velocity is: ``` v(t) = -0.65t² / 2 ``` 5. **Calculate the velocity at time t:** Since the final velocity is 15.3 m/s, we’ll have: ``` v(t) = 15.3 = -0.65t² / 2 ``` This gives: ``` -0.65t² / 2 = 15.3 ``` Solve for t: ``` -0.65t² = 30.6 t² = -30.6 / -0.65 t² = 47.076 t = √47.076 t = 6.86 s ``` Therefore, the time taken for the rocket to reach its final state velocity of 15.3 m/s is 6.86 seconds. 6. **Determine the acceleration:** Here, the acceleration is given by -0.65t. Therefore, at t = 6.86 s, the acceleration is: ``` a(t) = -0.65t = -0.65 × 6.86 = -4.459 m/s² ``` However, the final state velocity is achieved, so the acceleration becomes 0 m/s². This suggests that the rocket is no longer accelerating. 7. **Final state velocity:** Since the final state velocity is 15.3 m/s, the rocket is no longer accelerating, and the final velocity is 15.3 m/s. Therefore, the time taken for the rocket to reach its final state velocity of 15.3 m/s is 6.86 seconds.

19 Aug 2008

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