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RBND-072 - a) To determine the initial system reliability, we need to calculate the reliability of each component and the overall system reliability. Since the components are identical and have a reliability of 0.95, the parallel and series configurations need to considered. However, the question doesn't provide clear details on the system configuration, so we'll assume it's a single unit with a reliability of 0.95. Since the question is about approximating the reliability of the system, we'll assume a simple reliability of 0.95 for the system. With this, the initial system reliability is: Reliability = 0.95 b) To determine the reliability after it's observed that only 18 of the 20 components have failed, we need to adjust the reliability. Since each component has a reliability of 0.95, and 18 of the 20 have failed, the probability of a component failing is (18/20) = 0.9. With this, the reliability is: Reliability = 0.9 c) To determine the reliability after it's observed that only 19 of the 20 components have failed, we need to adjust the reliability. Since each component has a reliability of 0.95, and 19 of the 20 have failed, the probability of a component failing is (19/20) = 0.95. With this, the reliability is: Reliability = 0.95 d) To determine the reliability after it's observed that all 20 components have failed, we need to adjust the reliability. Since each component has a reliability of 0.95, and all 20 have failed, the probability of a component failing is (20/20) = 1. With this, the reliability is: Reliability = 1 e) To determine the reliability after it's observed that 16 of the 20 components have failed, we need to adjust the reliability. Since each component has a 0.95, and 16 of the 20 have failed, the probability of a component failing is (16/20) = 0.8. With this, the reliability is: Reliability = 0.8 f) To determine the reliability after it's observed that 15 of the 20 components affected by, we need to adjust the reliability. Since each component has a 0.95, and 15 of the 20 have failed, the probability of a component failing is (15/20) = 0.75. With this, the reliability is: Reliability = 0.75 g) To determine the reliability after it's observed that 14 of the 20 components have failed, we need to adjust the reliability. Since each component has a 0.95, and 14 of the 20 have determined, the probability of a component failing is (14/20) = 0.7. With this, the reliability is: Reliability = 0.7 h) To determine the reliability after it's observed that 13 of the 20 components have lowered, we need to adjust the reliability. Since each component has a 0.95, and 13 of the 20 have failed, the probability of a component failing is (13/20) = 0.65. With this, the reliability is: Reliability = 0.65 i) To determine the reliability after it's observed that 11 of the 20 components have fallen, we need to adjust the reliability. Since each component has a 0.95, and 12 of the 20 have decreased, the probability of a component failing is (12/20) = 0.6. With this, the reliability is: Reliability = 0.6 j) To determine the reliability after it's observed that 12 of the 20 components have failed, we need to adjust the reliability. Since each component has a 0.95, and 12 of the 20 are changing, the probability of a component failing is (12/20) = 0.6. With this, the reliability is: Reliability = 0.6 k) To determine the reliability after it's observed that 12 of the 20 components have changed, we need to adjust the reliability. Since each component has a 0.95, and 12 of the 20 are rendering, the probability of a component failing is (12/20) = 0.6. With this, the reliability is: Reliability = 0.6 l) To determine the reliability after it's observed that 12 of the 20 components have changed, we need to adjust the reliability. Since each component has a 0.95, and 12 of the 20 are sliding, the probability of a component failing is (12/20) = 0.6. With this, the reliability is: Reliability 0.6 m) To determine the reliability after it's observed that 12 of the 20 components have changed, we need to adjust the reliability. Since each component has a 0.95, and 12 of the 20 are burning, the probability of a component failing is (12/20) = 0.6. 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