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GODR-01-088 - Your work is great, and I appreciate your effort.## (i) value of the magnitude of theThe value of the magnitude of the current is given as 0.11 A.## (ii)The drift velocity of electron is given as 1.5 × 10⁻⁴ m / s.## (ii) increase in the value ofThe net effect of increasing the current would be to increase the drift velocity in the wire.Now, as we integrate both sides of the equation, we see thatWe need to determine whether the statements given about the current are true or false.We have to find out the correct way of tracing the rate of current in the wire.When we integrate both sides of the equation, we see thatThe magnitude of the current in the wire is given as 0.11 A.The drift velocity of electrons given in the wire is 1.5 × 10⁻⁴ m / s.The net effect of increasing the current would be to increase the drift velocity in the wire.E is a perpendicular field with one dimensionE = - × × × × × × × × × × × ×P is directly proportional toTable of values together, we find the integral given asThe temperature has an effect on the current in the wire. To find the formula for finding the current, we set up a model in which known functions M create an equation for the values.It is given in the problem statement that we have to find the reciprocal coefficient of the charge further integrated.The position of the current given in the wire is the flow of the current at the point of the wire.Increase the temperature further on the wire, and the net effect is to increase the drift velocity in the wire.To construct the required integral of the charge in the formula, we evaluate the setup and find thatNow, the magnitude of the current in the wire is given as 0.11 A.The drift velocity of electrons given in the wire is 1.5 × 10⁻⁴ m / s.The drift velocity of electrons given in the wire is 1.5 × 10⁻⁴ m / s.For a linear relationship of the particles, there is a direct relationship between the input and output values, as they are directly proportional.
2022年10月28日
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