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SAVR-236 Help me solve this problem: Given a quadratic equation ( ax^2 + bx + c = 0 ), a function is introduced ( f/one/2/3/1/3/ 1/2/2 0/0/0/3/0/1/0 -0 that can let you run the quadratic equation (****) , which votes of the function x1 = 1/3/1/3/ and x2 = 1/2/2/0/2/0/0 that give you a quadratic equation. What is the quadratic equation?** To determine the quadratic equation given the roots ( x1 ) and ( x2 ), we can use the formula: [ (x - x1)(x - x2) = 0 ] Given the roots ( x1 = frac{1}{3} ) and ( x2 = frac{1}{2} ), we substitute these values into the formula: [ (x - frac{1}{3})(x - frac{1}{2}) = 0 ] Now, expand the equation: [ (x - frac{1}{3})(x - frac{1}{2}) = x^2 - frac{1}{2}x - frac{1}{3}x + frac{1}{6} = 0 ] Multiply all terms by 6 to get integers: [ 6x^2 - 3x - 2x + 1 = 0 ] Combine like terms: [ 6x^2 - 5x + 1 = 0 ] Therefore, the quadratic equation is: [ ox{6x^2 - 5x + 1 = 0} ]

2023年3月17日89 分