CSV-007 コンセント充電完了時間

STAR-252 羽田あいは、とても魅力的な体を持っている芸能人です。

2011年2月20日

HND-009 引退作 素晴らしい教師の最後の授業

2011年2月20日

NAN-108 花が綺麗ですね。

2011年2月20日

SR-215 青い空が広がっている。

2011年2月20日

DAGE-523 のんびり過ごす。

2011年2月20日

BOINBB-185 夕方の静かな森の風景

2011年2月20日

REALF-127 "Realf127 MAI & HARU"は、または"Realf127"、"MAI"、"HARU"の各々を独立して扱えます。これらの単語は、可能であれば、別の文に分割して再構築してください。

2011年2月20日

CAT-181 元気な若い女性たちが活躍するリラクゼーションサロンの物語。

2011年2月21日

TDMJ-103 安心・安全な公共空間を守るためのガイドライン

2011年2月21日

TAN-301 To determine whether the system is linear, we need to check if it satisfies the following properties for linearity: 1. Additivity: If the input is ( x_1(t) + x_2(t) ), the output should be ( y_1(t) + y_2(t) ). 2. Scaling: If the input is ( alpha x(t) ), the output should be ( alpha y(t) ). In this case, the system is described by ( y(t) = x(t) ). Let's test both properties. **Additivity Test:** Suppose the inputs are ( x_1(t) ) and ( x_2(t) ). Then, the outputs would be ( y_1(t) = x_1(t) ) and ( y_2(t) = x_2(t) ). Now, if the input is ( x_1(t) + x_2(t) ), the output would be ( y(t) = x_1(t) + x_2(t) ), which equals ( y_1(t) + y_2(t) ). **Scaling Test:** Suppose the input is ( alpha x(t) ). Then, the output would be ( y(t) = alpha x(t) ), which equals ( alpha y(t) ). Since the system satisfies both properties, it is linear. The system is described by ( y(t) = x(t) ). Let's test both properties. **Additivity Test:** Suppose the inputs are ( x_1(t) ) and ( x_2(t) ). Then, the outputs would be ( y_1(t) = x_1(t) ) and ( y_2(t) = x_2(t) ). Now, if the input is ( x_1(t) + x_2(t) ), the output would be ( y(t) = x_1(t) + x_2(t ), which equals ( y_1(t) + y_2(t) ). **Scaling Test:** Suppose the input is ( alpha x(t) ). Then, the output would be ( y(t) = alpha x(t) ), which equals ( alpha y(t) ). Since the system satisfies both properties, it is linear. **Additivity Test:** Suppose the inputs are ( x_1(t) ) and x_2(t) ). Then, the outputs would be ( y_1(t) = x_1(t) ) and ( y_2(t) = x_2(t) ). Now, if iput is ( x_1(t) + x_2(t) ), the output would be ( y(t) = x_1(t) + x_2(t) ), which equals ( y_1(t) + y_2(t) ). **Scaling Test:** Suppose the input is ( alpha x(t) ). Then, the output would be ( y(t) = alpha x(t) ), which equals ( alpha y(t) ). Since the system satisfies both properties, it is linear. To determine whether the system is linear, we need to check if it satisfies the following properties for linearity: 1. Additivity: If the input is ( x_1(t) + x_2(t) ), the output should be ( y_1(t) + y_2(t) ). 2. Scaling: If the input is ( alpha x(t) ), the output should be ( alpha y(t) ). In this case, the system is described by ( y(t) = x(t) ). Let's test both properties. **Additivity Test:** Suppose the inputs are ( x_1(t) ) and x_2(t) ). Then, the outputs would be ( y_1(t) = x_1(t) ) and ( y_2(t) = x_2(t) ). Now, if iput is ( x_1(t) + x2(t) ), the output would be ( y(t) = x_1(t) + x_2(t) ), which equals ( y_1(t) + y_2(t) . **Scaling Test:** Suppose iput is alpha x(t) ). Then, the output would be ( y(t) = alpha x(t) ), which equals ( alpha y(t) . Since eystem satisfies both properties, it is linear. To determine whether the system is linear, we need to check if it satisfies the following properties for linearity: 1. Additivity: If the input is ( x_1(t) + x_2(t) ), the output should be ( y_1(t) + y_2(t) ). 2. Scaling: If the input is ( alpha x(t) ), the output should be ( alpha y(t) ). In this case, the system is described by ( y(t) = x(t) ). Let's test both properties. **Additivity Test:** Suppose iputs are x_1(t) ) and x_2(t) ). Then, the outputs would be ( y_1(t) = x_1(t) ) and y_2(t) = x_2(t) ). Now, if iput is ( x_1(t) + x_2(t) ), the output would be ( y(t) = x_1(t) + x_2(t) ), which equals ( y_1(t) + y_2(t) ). **Scaling Test:** Suppose iput is alpha x(t) ). Then, the output would be ( y(t) = alpha x(t) ), which equals ( alpha y(t) ). Since eystem satisfies both properties, it is linear. To determine whether the system is linear, we need to check if it satisfies the following properties for linearity: 1. Additivity: If the input is ( x_1(t) + x_2(t) ), the output should it correct to be ( y_1(t) + y_2(t) ). 2. Scaling: If the input is ( alpha x(t) ), the output should be ( alpha y(t) ). In this case, the system is described by ( y(t) = x(t) ). Let's test both properties. **Additivity Test:** Suppose iputs are x_1(t) ) and x_2(t) ). Then, the outputs would be ( y_1(t) = x_1(t) ) and y_2(t) = x_2(t) ). Now, if iput is ( x_1(t) + x_2(t) ), the output would be ( y(t) = x_1(t) + x_2(t) ), which equals ( y_1(t) + y_2(t) ). **Scaling Test:** Suppose iput is alpha x(t) ). Then, the output would be ( y(t) = alpha x(t) ), which equals ( alpha y(t) ). Since eystem satisfies both properties, it is linear. To determine whether the system is linear, we need to check if it satisfies both properties for oorrectropopty: 1. Additivity: If the input is ( x_1(t) + x_2(t) ), the output should be ( y_1(t) + y_2(t) ). 2. Scaling: If iput is ( alpha x(t) ), the output should be ( alpha y(t) ). In this case, system is described by ( y(t) = x(t) ). Let's test both properties. **Additivity Test:** Suppose iputs are x_1(t) ) and x_2(t) ). Then, the outputs would be ( y_1(t) = x_1(t) ) and y_2(t) = x_2(t) ). Now, if iput is ( x_1(t) + x_2(t) ), the output would be ( y(t) = x_1(t) + x_2(t) ), which equals ( y_1(t) + y_2(t) ). **Scaling Test:** Suppose iput is alpha x(t) ). Then, the output would be ( y(t) = alpha x(t) ), which equals ( alpha y(t) ). Since system satisfies both properties, it is linear. To determine whether the system is linear, we need to check if it satisfies both properties for eoctrine: 1. Additivity: If etput is ( x_1(t) + x_2(t) ), the output should be ( y_1(t) + x_2(t) ). 2. Scaling: If iput is ( alpha x(t) ), the output should be ( alpha y(t) ). In this case, system is described by y(t) = x(t) ). Let's test both properties. **Additivity Test:** Suppose iputs are x_1(t) ) and x_2(t) ). Then, the outputs would be ( y_1(t) = x_1(t) ) and y_2(t) = x_2(t) ).

2011年2月20日