SAVR-236 Help me solve this problem: Given a quadratic equation ( ax^2 + bx + c = 0 ), a function is introduced ( f/one/2/3/1/3/ 1/2/2 0/0/0/3/0/1/0 -0 that can let you run the quadratic equation (****) , which votes of the function x1 = 1/3/1/3/ and x2 = 1/2/2/0/2/0/0 that give you a quadratic equation. What is the quadratic equation?** To determine the quadratic equation given the roots ( x1 ) and ( x2 ), we can use the formula:
[
(x - x1)(x - x2) = 0
]
Given the roots ( x1 = frac{1}{3} ) and ( x2 = frac{1}{2} ), we substitute these values into the formula:
[
(x - frac{1}{3})(x - frac{1}{2}) = 0
]
Now, expand the equation:
[
(x - frac{1}{3})(x - frac{1}{2}) = x^2 - frac{1}{2}x - frac{1}{3}x + frac{1}{6} = 0
]
Multiply all terms by 6 to get integers:
[
6x^2 - 3x - 2x + 1 = 0
]
Combine like terms:
[
6x^2 - 5x + 1 = 0
]
Therefore, the quadratic equation is:
[
ox{6x^2 - 5x + 1 = 0}
]
2023年3月17日